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Matrices & Determinants ​

Linear Algebraic Viewpoint

A matrix represents a linear transformation between vector spaces. The determinant det(A) quantifies the oriented scaling factor of volume under this transformation. In competitive exams, mastery spans determinant row/column operations, adjoint-determinant identities, characteristic polynomials, and solvability of linear systems.


1. Properties of Determinants ​

📊Visual Mathematical Intuition
Determinant as Signed Parallelogram Area & Linear Mapping
u⃗ = (a, b) v⃗ = (c, d) (a+c, b+d) Area = |ad - bc| If det(A) = 0, vectors u and v are collinear, Area collapses to zero.
Signed Area:det⁡(abcd)=ad−bc=Area(u⃗,v⃗)\det\begin{pmatrix} a & b \\ c & d \end{pmatrix} = ad - bc = \text{Area}(\vec{u}, \vec{v})
Orientation:det⁡(A)>0  ⟹  Preserves,  det⁡(A)=0  ⟹  Collapses to Line\det(A) > 0 \implies \text{Preserves}, \; \det(A) = 0 \implies \text{Collapses to Line}

A 2×22 \times 2 determinant equals the signed area of the parallelogram spanned by column vectors u⃗\vec{u} and v⃗\vec{v}. When det⁡(A)=0\det(A) = 0, the parallelogram collapses into a degenerate 1D line.

  1. Transpose Invariance: det(AT)=det(A)
  2. Row/Column Interchange: Swapping two rows/columns flips the sign of det(A).
  3. Scalar Multiplication: det(kA)=kndet(A) for an n×n matrix A.
  4. Multiplicative Property: det(AB)=det(A)⋅det(B)
  5. Elementary Operations: Adding a scalar multiple of one row to another preserves det(A).

2. Adjoint and Inverse of a Matrix ​

For an n×n invertible matrix A (det(A)≠0):

A⋅adj(A)=adj(A)⋅A=det(A)⋅InA−1=1det(A)adj(A)

Critical Adjoint Identities ​

IdentityFormula
Determinant of Adjointdet(adj(A))=(det(A))n−1
Adjoint of Adjointadj(adj(A))=(det(A))n−2A
Determinant of Double Adjointdet(adj(adj(A)))=(det(A))(n−1)2
Inverse of Transpose(AT)−1=(A−1)T
Reversal Law(AB)−1=B−1A−1 and adj(AB)=adj(B)⋅adj(A)

3. Cayley-Hamilton Theorem & Characteristic Polynomial ​

Cayley-Hamilton Theorem

Every square matrix A satisfies its own characteristic equation:

det(λI−A)=0⟹λn+cn−1λn−1+⋯+c0=0⟹An+cn−1An−1+⋯+c0I=0

For a 2×2 matrix A=(abcd):

A2−tr(A)A+det(A)I=0where tr(A)=a+d

4. System of Linear Equations (Solvability Criteria) ​

Consider AX=B with coefficient matrix A and augmented matrix [A|B]:

  1. Unique Solution: det(A)≠0 (Rank A = Rank [A|B] = n).
  2. Infinitely Many Solutions (Consistent): det(A)=0 AND (adj(A))B=0 (Rank A = Rank [A|B]<n).
  3. No Solution (Inconsistent): det(A)=0 AND (adj(A))B≠0 (Rank A<Rank [A|B]).